WebSep 7, 2024 · The nth term of a GP is given by tn = arn-1 where a is the first term and r is the common ratio The pth term (tp) of both AP and GP is a For AP ⇒ tp = m + (p – 1)d ⇒ a = m + (p – 1)d … (u) For GP ⇒ tp = lsp-1 ⇒ a = lsp-1 … (v) The qth term (tq) of both AP and GP is b For AP ⇒ tq = m + (q – 1)d ⇒ b = m + (q – 1)d … (w) For GP ⇒ tq = lsq-1 WebJul 15, 2024 · a p+q = m. a p-q = n. a n = ar n-1 . a p+q = a.r p+q-1 . a p-q = a.r p-q-1 . ∴ a.r p+q-1 = m. a.r p-q-1 = n. Multiplying above two equations we get . a 2 r (p+q-1+(p-q-1) = a …
If p+qth term of a G.P be m and p qth term be n, then the pth term …
WebMar 30, 2024 · Prove that aq r br p cp q = 1 We know that nth term of G.P = ARn 1 (We are using a, r in the question, so we use A for first term and R for common ratio) It is given that pth term of G.P = a Ap = a ARp 1 = a a = ARp 1 aq r = ("ARp 1")q r We need to show that aq r br p cp q = 1 Also, qth term of G.P = b Aq = b ARq 1 = b b = ARq 1 br p = (ARq 1)r p … WebIn G.P. (p+q) th term is m, (p−q) th term is n, then p th term is A nm B nm C nm D nm Medium Solution Verified by Toppr Correct option is B) Let the first term of G.P be 'a' and common ratio be 'r' given T p+q=ar p+q−1=m T p−q=ar p−q−1=n then multiplying the … simphy download
If (P + Q)Th and (P − Q)Th Terms of a G.P. Are M and N …
WebHere are the GP formulas for a geometric progression with the first term 'a' and the common ratio 'r': n th term, a n = ar n-1. Sum of the first 'n' terms, S n = a(1-r n)/(1-r) when r ≠ 1. … WebIf in a GP the (p+q) th term is a and the (p−q) th term is b, then p th term is A (ab) 1/3 B (ab) 1/2 C (ab) 1/4 D None of these Hard Solution Verified by Toppr Correct option is B) Let the G.P. be x,xy,xy 2,... Then t p+q=xy p+q−1=a ... (1) and t p−q=xy p−q−1=b ... (2) Dividing (1) by (2), y 2q= ba⇒y=(ba)1/2q From (1), x=a(ab)(p+q−1)/(2q) WebMar 30, 2024 · Transcript. Example 21 If pth, qth, rth and sth terms of an A.P. are in G.P, then show that (p – q), (q – r), (r – s) are also in G.P. We know that the nth term of AP is a + (n – 1)d i.e. an = a + (n – 1)d It is given that ap, aq, ar & as in GP i.e. their common ratio is same So,𝑎_𝑞/𝑎_𝑝 = (ar )/qq = 𝑎𝑠/𝑎𝑟 We need to show (p – q), (q – r), (r – s) are in ... sim photo printing