WebMar 30, 2015 · 647 2 8 33 1 You need to allocate memory for the all the structs, e.g. n->desc. Just because you allocated memory for the parent struct it doesn't mean that somehow any child structs that they refer to will be magically be allocated - you have to do that yourself. Well done for using valgrind to identify the bugs though. – Paul R WebMar 30, 2012 · ==10463== Invalid write of size 8 ==10463== at 0x400C5D: checkDir (dirtree.c:96) ==10463== by 0x400F53: main (dirtree.c:135) ==10463== Address 0x51f88d8 is 0 bytes after a block of size 8 alloc'd ==10463== at 0x4C28F9F: malloc (vg_replace_malloc.c:236) ==10463== by 0x400BED: checkDir (dirtree.c:93) ==10463== …
Understanding Valgrind’s messages - Technical Documentation 1.3.38
WebJan 27, 2016 · You probably meant sizeof (*param) sizeof (*param) is the same as sizeof (typeof (*param)), which is the same as sizeof (CalParam). Types are constant, so sizeof is known at compile-time, so flexible arrays must be ignored in the count. As such, param = realloc (param, sizeof (param) + sizeof (char*)); should be WebApr 6, 2012 · It turns out there were a bunch of #IFDEFs in the class definition, so when I was compiling my utility against the library built with the projects makefile it was using the source headers and thought the class had a different amount of properties, so they were not arranged in memory correctly and got crushed by the allocation of the arrays. green creative 58285
c++11 - Valgrind throws Invalid write of size 8 using smart …
WebNov 10, 2016 · When running the code it compiles completely without error and still outputs the right output. ==23609== Invalid write of size 8 ==23609== at 0x400800: matCreate ==23609== by 0x4010E2: main ==23609== Address 0x5203048 is 0 bytes after a block … WebFeb 18, 2015 · You specify the wrong amount of memory for allocate the structure: if ( (*dstr = malloc (sizeof *dstr)) == NULL) Since dstr is (struct dstr **), then sizeof (*dstr) is the size of pointer, not the size of structure. To fix that, you might want to write it in this way: if ( (*dstr = malloc (sizeof **dstr)) == NULL) Share Improve this answer Follow WebTo resolve the invalid read of size 8 error, the programmer has to ensure the structure of the array is proper and that there are no syntax errors. Other resolutions of this error include using proper protocols to free the SYM. Moreover, resolving memory leak issues also fixes this error. – Free “SYM” Properly floyd county commissioners georgia